moodaeng

1. Find what is 1*. By using equation p* = (p/2) / (4p-1) replace p with 1. 1* = (1/2) / ( (4*1) - 1) Yes! you get 1* = 1/6. 2. Ok we know q = 1* from the question Then q = 1/6 3. Find q*. Then you will get the answer. Which is -1/4. replace p* = (p/2) / (4p-1) with q you will get q* = (q/2) / (4q-1) replace q = 1/6. Then (1/6)* = (1/6 / 2) / (4*(1/6) - 1) (1/6)* = -1/4

Pick the first sock with no requirement. so we don't have to care about Prob. However the second sock we have to pick with the same color as the first one. So there is only 1 sock that has similar color with the 1st sock from 9 socks. Ans is 1/9

12. In every month, a hospital is opened only in last week. If 10 people travel through bus to hospital, what is the probability that atleast two people travel on the same day? 10 people in 7 days (Mon - Sun) The reverse way to ask this question is "How can you make all people go to hospital in different days? No right? So the answer is 1 ------------------------------------ Mon--Tue--Wed--Thu--Fri--Sat--Sun Mr1...Mr2...Mr3...Mr4...Mr5...Mr6...Mr7 Mr. 1 to 7 already choose the days that they want to go to the hospital. So how can you make Mr8,Mr9,Mr10 to go to hosipital with different days from Mr1-Mr7 Of course, it is impossible.

It is imposible because the number inside sqrt() should be possitive or zero. However if the number is negative, it will be something called "Imaginary number" (not Real number and not in gre exam) And Imaginary number is not negative number. the result of the sqrt() will be >= 0 How about? sqrt(x^2) = |x| |x| = x when x > 0 OR = 0 when x = 0 OR = -x when x No for example |-3| = -(-3) = 3 (positive number) :D Good luck for yr test .

2sqrt(xy) can be positive or zero since x and y are not zero Then 2sqrt(xy) is only positive number (x and y are real numbers)

I think High school statistics is enough

list1 should be 0 ..... 16 (so the range of this list is 16) list2 should be 0 .......10 (so the range of this list is 10)

I used my high school math and my Computer Math books.

2. Compare to 5 * 5 = 25 4 * 6 = 24 3 * 7 = 21 Get an idea?

2n+1 - 2n = 1000? You can do this way only the question is like this; 2^2n+1 * 2^2n = 2^1000, not this; 2^2n+1- 2^2n = 2^1000. 2^2n (2-1) = 2^1000 2^2n = 2^1000 2n = 1000 n = 500

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2. If x Col a: x Col b: 0 x^2 - xy = 0 x(x-y) = 0 so we get x = 0 OR x - y = 0 , x = y but this one is impossible because x finally we get only x = 0 and x Then the answer is C

Yep, I think so. Both can have same SD. for example; all student weights = their means. Then SD = 0

I think Geometry questions in GRE are very tricky especially when they mix with Quantitive comparison.

Oh Yes. hahahaha :p

for the full Chinese reminder thorem you can find online. But for GRE I think the simple Chinese Reminder is enough

When you find a question such as .... divided by 5 and reminder is 3, divided by 7 reminder is 5.. This kind of question you have to use Chinese reminder to solve it for example If a number is divisible by 5 the remainder is 3 and when the same number is divided by 7 the remainder is 4. What is the least possible number? "a number is divisible by 5 the remainder is 3" we can make an equation from this sentence: n = 5a + 3 --(eq1) ;where a = Integer (both positive and negative) "divided by 7 the remainder is 4" n = 7b + 4 --(eq2) ;where b = Integer OR we can rewrite (eq2) as n = 4 (mod 7) ----(eq3) ; another ways to represent (eq2) Then we use n value from (eq1) in (eq3). we will get 5a + 3 = 4 (mod 7) 5a = 1 (mod 7) --(eq4) ; move 3 to right side to minus 4 Then think some number that mutiply 5 (from 5a) and divided by 7 the reminder is 1 (this is a step to eliminate coefficient of "a") for now,this questsion, the number is very easy to find, I get 10 10 x (eq4) 50a = 10 (mod 7) --(eq5) Then we modulo both side by 7 1*a = 3 (mod 7) a = 3 (mod 7) ---(eq6) from (eq 6) we can write back to a normal reminder equation a = 7b + 3 ----(eq7) Then we use value "a" from (eq7) to (eq1) n = 5(7b+3) + 3 n = 35b + 15 + 3 n = 35b + 18 -----(eq8) Yes we get final equation for n. The question usually ask the "what is smallest positive number of n" I choose b = 0 n = 35(0) + 18 n = 18 Yeah. Finally................................... Ans is 18 The next numbers are b = 1, 2, 3 ..... and put in (eq8) n = 53, 88...... .

1.Col A: The standard deviation of 10, 20, 50, 80, 90. Col B: The standard deviation of 11, 30, 50, 70, 90. SD = standard deviation (from mean) ColA mean is 50 ColB mean is about 50 if you see the number 20 (colA) and 30 (ColB) 20(ColA) is more deviate from 50(mean) than 30 and 80 (ColA) is more deviate from 50(mean) than 70 11(ColA) is a little bit less deviate from 50(mean) than 10(colB) The answer is A 2) The question should be "[z] represents greatest integer" 6) Given that, if a person has 5 pair of socks of different colors and if 2 are chosen at random then what is the probability that both of them are of same color? Think there are 10 socks you pick 1 sock. so there will be 9 left and you pick another one that has a same color as the first one There is only 1 sock from 9 socks that has a same color, right? So the answer is 1/9 Yes

Hahah Thank everybody. Yep orkut database = Real GRE I confirm At least 2-3 questions in your exam

what is #6?

٩(-̮̮̃-̃)۶ Yeah! I am done with Maths

I think quantitave score is predictable from simulator software. I get 750-800 Cambridge GRE Prep1 750-800 Cambridge GRE Prep2 790 Peterson 800 Peterson 29/30 Kaplan book 29/30 Nova 770 ETS test Prep1 790 ETS test Prep2 I know my score will be around 770-800

Graph problems are Mind-tester, I think. This type of question is not hard But need time for reading and calculating If you are working on these questions and you see a clock, there is 5 mins left (Damm! I have 10 questions left). Calm down! I think it is the best way. (But I cannot do it haahahha)

see that end of number "2" will end at 3 rd place 3 will end at 6nd place number "n" will end at n*(n+1)/2 place so you will find some number that end close to 100 i get 14 will end at 14 * (14+1)/2 = 105nd so you will have something like this pos_97__98__99__100__101__102__103__104__105__106__107 num_14__14__14 __14___14___14___14___14___14___15___15 .................

GRE questions from Dr Raju are real GRE. I confirm Work hard on them. 6 months back I think It will be enough