saifgre

Congrates for your quantitative section. How can we solve graph problem quickly? is there any suggestion from your side? could you plz write a suggestive article on it? Thanx a lot for your contribution.

IMO distinct positive factors are 1 7 19 19.19 19.19.19 7.19 7.19.19 7.19.19.19 total 8 different numbers.

Try to find out the overall ratio of diamond : rubi : emeralds easiest way is to convert 5/6 and 8/3 in such a that denominator of 5/6 and nominator of 8/3 become equal. as, multiple the first ration by 4 and multiply second ration by 3. it results 20/24 and 24/9. Now, we can write diamond : Rubi : emeralds = 20:24:9 Is there any common divisor? no. so minimum possible # of jewels are 20+24+9=53

Removing corner cube will loose area of 3 unit. however, Removing that cube will open 3 new unit area. thats why the resultant 'surface area' will not be change. Becareful, this question doesn't ask about changing volume.

for Q2. lets consider ....,-2, -1, 0, 1, 2, 3 ... -1, 0, 1=0 -1...2 =2 0 1 2 =3 0 1 2 3=6 -1 .....3=5 can u plz give an example that sums up to 4???

favorable outcomes for x+y>=9 are (3,6), (4,6) (5,6) (6,6) (4,5), (5,5), (6,5) (5,4),(6,4) (6,3) In total 10 favorable outcomes.

I think u r corrent for the first part where sum is 9 (say x + y = 9) But for, at least 9, x + y >= 9, let us explain. (3|4|5|6) + 6 >= 9 (4|5|6) +5 >=9 (5|6)+4>=9 6+3 >=9 total 10 out of 36 choices resulting probability of 10/36. Am I correct?

let property = x tax rate =y Old tax = xy New property = x - x/4 = (3/4)x New tax = y+y/4 = (5/4)y New tax = 15/16 xy Old tax - new tax = 1/16 = 6.25%

Q2. (Soup or salad)*(sandwich)*(tea or coffee)*(dessert) = (3+2)*7*2*8 =560

thanx

To me it seems, 1) a 2)varies 3)2 (guess) 4)115 5)(36*12)/4=108 (guess) 6)3^4=81 7)1 8)A

Answers: 1) a 2)b 3)d 4)a 5)col A=Col B

Moodaeng's solution looks logical.

Dear Jess John, The question that you hv answered, is "what is the probability of choosing a yellow pencil with an eraser." But in the question it is given that a yellow pencil has already been chosen. Now, we hv to find the probability of a yellow pencil with eraser. Thats why formula (1) should be used. thanx

Dear Jess John, The question that you hv answered, is "what is the probability of choosing a yellow pencil with an eraser." But in the question it is given that a yellow pencil has already been chosen. Now, we hv to find the probability of a yellow pencil with eraser. Thats why formula (1) should be used. thanx