Alexey_KLexxRuss

It's E b/s at least 3 of 4 Traux's shipments were buidings and could be sent on Friday and no less than 1 coul be sent before

(1) suff itself while '2345123' is odd

2^15+2^16+2^17=7*2^15

what dont you understand. clarify

Angle(x=360-1*v+4*v; x->0)=360*1/5 1/5*96*pi*2=120.576. Is correct answer 121?

1. sequences with one E: 7*6*5*4*3=2520 2. others: 6*5*4*2c5=120*10=1200 total: 3720

The number of commitees of 6 from group of 10 people is 6c10 = 210, the probability of 2 persons to be taken into the same commitee is 6/10*5/9 or 1/3 so number of commitees without vise- and president together are 210*2/3 or 140 Óìåþ êàòàòüñÿ íà âåëîñèïåäå ñ çàêðûòûìè ãëàçàìè :)

it's easy. This outcomes are: HHHH and TTTT (total 2) Óìåþ êàòàòüñÿ íà âåëîñèïåäå ñ çàêðûòûìè ãëàçàìè :)

In the math book you can see () that proportion of items with normal distribution depending on mean and standart deviation is 68%:95%:99%:100% (M+1sd, 2sd, 3sd, more) or in language of 34:14:2 it is 34:13,5:2:0,5 and the correct answer is 5/32 (not 1/8)

Total variants n!=5!=120. Required variants are: c1 c2 s c2 c1 * 4 c1 s c2 c1 c2 * 4 c2 s c1 c2 c1 * 4 c1 c2 c1 s c2 * 4 c2 c1 c2 s c1 * 4 => The probability is 20/120 = 1/6 Ðóññêèå èäóò :p

Total number of variants is 7*6*5. The number of variants between 300 and 700 is 4*6*5 and the number of variants between 650 and 700 is 10 (51. 52. 53. 54. 57. 71. 72. 73. 74. 75 :) ). The resulting probability is (4*6*5-10)/(7*6*5) = 110/210 or 11/21 hence A

125 8)

10^1 - 2 digit (10) 10^2 - 3 digit (100) 10^100 - 101 digit (10000000000000000000000000000000000000000 0000000000000000000000000000000000000000000000000000000000 0000000000000000000000000000000000) :) Tabletop: sideA = 3ft sideB = x/3 (ft) LengthStrip = 3*2+2*x/3 = 6 + 2/3 x = x => x = 18ft (Length) and sideB = 18/3 = 6ft

We can solve it in 1 easer way: 1) P of inacurate record is 3%+(0..3%)

0,1x+2*0,5=(x+2)*0,15 => x=14