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Alexey_KLexxRuss

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Everything posted by Alexey_KLexxRuss

  1. It's E b/s at least 3 of 4 Traux's shipments were buidings and could be sent on Friday and no less than 1 coul be sent before
  2. (1) suff itself while '2345123' is odd
  3. Angle(x=360-1*v+4*v; x->0)=360*1/5 1/5*96*pi*2=120.576. Is correct answer 121?
  4. 1. sequences with one E: 7*6*5*4*3=2520 2. others: 6*5*4*2c5=120*10=1200 total: 3720
  5. The number of commitees of 6 from group of 10 people is 6c10 = 210, the probability of 2 persons to be taken into the same commitee is 6/10*5/9 or 1/3 so number of commitees without vise- and president together are 210*2/3 or 140 Óìåþ êàòàòüñÿ íà âåëîñèïåäå ñ çàêðûòûìè ãëàçàìè :)
  6. it's easy. This outcomes are: HHHH and TTTT (total 2) Óìåþ êàòàòüñÿ íà âåëîñèïåäå ñ çàêðûòûìè ãëàçàìè :)
  7. In the math book you can see () that proportion of items with normal distribution depending on mean and standart deviation is 68%:95%:99%:100% (M+1sd, 2sd, 3sd, more) or in language of 34:14:2 it is 34:13,5:2:0,5 and the correct answer is 5/32 (not 1/8)
  8. Total variants n!=5!=120. Required variants are: c1 c2 s c2 c1 * 4 c1 s c2 c1 c2 * 4 c2 s c1 c2 c1 * 4 c1 c2 c1 s c2 * 4 c2 c1 c2 s c1 * 4 => The probability is 20/120 = 1/6 Ðóññêèå èäóò :p
  9. Total number of variants is 7*6*5. The number of variants between 300 and 700 is 4*6*5 and the number of variants between 650 and 700 is 10 (51. 52. 53. 54. 57. 71. 72. 73. 74. 75 :) ). The resulting probability is (4*6*5-10)/(7*6*5) = 110/210 or 11/21 hence A
  10. 10^1 - 2 digit (10) 10^2 - 3 digit (100) 10^100 - 101 digit (10000000000000000000000000000000000000000 0000000000000000000000000000000000000000000000000000000000 0000000000000000000000000000000000) :) Tabletop: sideA = 3ft sideB = x/3 (ft) LengthStrip = 3*2+2*x/3 = 6 + 2/3 x = x => x = 18ft (Length) and sideB = 18/3 = 6ft
  11. We can solve it in 1 easer way: 1) P of inacurate record is 3%+(0..3%)
  12. Easy one (while i spent some time thinking). Let center of the circle to be D. Teorem is that if PRO is 35° then PDO is 2*35°=70° hence PDQ = 180 - 2*70 = 40°. And arc PQ =π*OR* 40/360=2π
  13. yes you got :), hope my mental processes are not boring :crazy:
  14. for faster multiplying - as i know use of calculators is impossible on real n=gmat
  15. =(99999+1)*(99999-1 or 100000-2)=10^5*(10^5-2)
  16. 28 - number of 100$ chips 112 - number of 20$ chips x - number of chips in bet, hence (112-0,9x)/(140-x)=0,7 =>112-0,9x=98-0,7x =>0,2x=14 => x=70 Money bet = 70*0,1*100$+70*0,9*20$=700$+1260$=1960$ (A)
  17. 1996 x+y=(x+y) 1997 0.89x+1.07y=(x+y)*1,01 =>0,06y=0,12x=>y=2x => 1:2
  18. N = 2C11*2C9 = 55*36 = 1800+180=1980 (E)
  19. number of choises is 10*8*6 = 480. - but there there are the same choises like ABC and BAC arranged in 3!=6 ways. So, the answer is 480/6 = 80
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