kathy

Ans to Q1 : 4 when k is divided by 6 remainder is 5. We will assume some value of k...lets say 11 0r 17(for both the numbers remainder is 5 when divided by 6) if k is 11 or 17, 2k is 22 or 34. if we divide 22 by 6, remainder is 4. if we divide 34 by 6 remainder is again 4. So the answer is 4.

Hi Manasi, 30-60-90 Traingle rule : lenght of side opposite to 30 angle = 1/2 (length of side opposite to 90) lenght of side opposite to 60 angle = sqrt(3)/2 (length of side opposite to 90) I guess its clear now.

Q 1 : I didn't get first part of ur question....why its given ..in second part simple question is what is remainder when 21 is divided by 6 and the answer is 3. I don't think this question would be so simple. Is anything missing in question??? Ans : 3 Q 2 : I went on writing down the dates and I got the answer 6. There must be easiest way to solve this. If anyone knows...please do reply. Ans : 6 Q 3 : Center of Circle is O, point on line OC is D & point on circle is E. So, now we have to find perimeter of DEC. Perimeter of circle = 2xpix1 Angle x=30 Hence adjacent angle EOD is 60. Perimeter of EC = (60/360)x (2xpi) =(1/3)xpi Angle EOD=60, angle EDO=90 So, angle OED=30 OD=1/2(OE) ---------------------- as per rule of 30-60-90 triangle =1/2 DE={sqrt(3)/2}xOE ----------------as per rule of 30-60-90 triangle =sqrt(3)/2 DC=OC-OD=1-1/2=1/2 Perimeter of DEC = EC+DE+DC =pi/3+sqrt(3)/2+1/2 Ans : pi/3+sqrt(3)/2+1/2 Q 4 : Final value of Mutual Fund = $72.04billion Initial value of Mutual Fund = 72.04 + 3.04=$75.04billion Approximate percentage decrease in assets = (3.04/75.08)x100 = (300/7500)x100 (figures are rounded for simplification) = 4.0 Ans : 4%

252^5=(7x6^2)^5=(7^5)x(6^2)^5 =(7^5)x(6^10) 252^5 is divisible by 6^10 hence n=10

Hi Charanya, Ur question is not clear to me . I guess u r missing some part of question. If I solve above problem I get various answers....0,1,2,3,4,5,6 etc....there is no specific answer so this can't be a GRE question

I would also go with A. Distance travelled in 6 hrs is 480km, ie.average speed is 80 Distance travelled in 4 hrs is 300Km, ie. average Speed 75

I also got X = 390.09

Grecracker is right...answer should be C. I was wrong I haven't consider that each number should be min 8

Let me explain... let x be original price of each mango. and let y be no of magoes u get for Rs.x then 80 = y * x; and second equation is (0.8)*x*(y+40)=80 0.8xy + 32x =80 0.8*80 + 32x=80 (since xy=80) 64 + 32x = 80 32x = 16 x = 0.5 I solved it this way... I don't know how Vishal has soved for y first &then x:hmm:

I also got the same answer 0.5

Hey Nirmalya, U have got all correct.

Q 1. http://www.wtamu.edu/academic/anns/mps/math/mathlab/gre/gre_test1prob15.gif Find the area of the graph above enclosed by figure ABCD. A) 36 B) 30 C) 42 D) 72 E) 84 2. If account codes for a certain company are assigned as follows: two letters and then three one digit numbers, how many different account codes can be made? Note that letters and digits can be repeated. A) 1,757,600 B) 67,6000 C) 260 D) 67,600 E) 6,760 3. http://www.wtamu.edu/academic/anns/mps/math/mathlab/gre/gre_test1prob26.gif Looking at the figure above, if triangle ABC is an equilateral triangle and line BC is parallel to line DE, what is the measure of angle 5? A) 60 degrees B) 90 degrees C) 120 degrees D) 180 degrees E) Not enough information is given to answer this question 4. http://www.wtamu.edu/academic/anns/mps/math/mathlab/gre/gre_test1prob16a.gif Column A http://www.wtamu.edu/academic/anns/mps/math/mathlab/gre/gre_test1prob16b.gifColumn B -10 A) Column A’s quantity is greater. B) Column B’s quantity is greater. C) The quantities are the same. D) The relationship cannot be determined from the information given.

no we can't solve it without sin approach, At least I am not aware of any other method. kathy

hi, I guess in the question it is not mentioned ...and if that is not given then the question is wrong ...we can't get any answer. Only possibility is that angle Y + adjacent angle =90, then only we can solve this problem. So, I think if "bd" can clear that then my method is right otherwise.............don't know. kathy

First join points C & G Now area of shaded region = area of triangle CEF - area of triangle CDG Let's say side of square is R. then Area of triangle CEF =1/2 x length CE x length EF = 1/2 R x R=R^2/2 area of triangle CDG = 1/2 area of triangle BCD = 1/2(1/2 x length of BC x legth of CD) = 1/2(1/2 x R/2 x R/2) = R^2/16 Area of shaded region = R^2/2 - R^2/16 = 7R^2/16 Area of square ACEF = R^2 so, area of shaded region/area of square ACEF =7/16 column A=column B ANS : C