vnf

I'm a "sis", Jay :p

The unit digit of the total remaining cards is 6 => 180 - 176 = 4 (the value of each card is not greater than 9)

4(1 + 2 + ... + 9) = 180 (1) => The removed card must be 4 => suff (2) suff Hence, (D)

(E) is the answer, Jay. Just solve the equalities and represent the values on the horizontal axis, you can see it clearly. Only values of x from (E) equality ( -2/3

(E) it is

For (B)

© it is J1 = Jason's salary in 1995 J2 = Jason's salary in 1998 K1 = Karen's salary in 1995 K2 = Karen's salary in 1998 (J2 - J1)/J1 = (K2 - K1)/K1 (1) K1 = 2,000 + J1 => insuff (2) K2 = 2,440 + J2 => insuff (1) & (2) => (J2 - J1)/J1 = (2,440 + J2 - 2,000 - J1)/(2,000 + J1) => (J2 - J1)/J1 = (440 + J2 - J1)/(2,000 + J1) => 2,000(J2 - J1) + J1(J2 - J1) = 440J1 + J1(J2 - J1) => (J2 - J1)/J1 = p = 440/2,000 => suff

4a = 2*pi*r => a = pi*r/2 Area S/Area C = (a^2)/(pi*r^2) = (pi^2)*(r^2)/4*(pi*r^2) = pi/4 = 3/4 (approx) Hence, (B)

For (B)

-2x > 3y Is x negative? (1) y > 0 => -2x > 3y > 0 => x must be -ve => suff (2) 2x + 5y - 20 = 0 => - 2x = 5y - 20 > 3y => 2y > 20 => y > 10 => -2x > 3y > 30 > 0 => y must be -ve => suff Hence, (D)

x = a/2 + b/2^3 + c/a^4 = (8a + 2b + c)/16 If a, b, c are equal to 0 or 1, x can be equal to all the choices except ©

(B) it is (1) Clearly insuff (2) (s1 + s2 + s3)/3 = 78 (1) (s1 + s2 + s3 + s4)/4 = 90 (2) (1) & (2) => can firgure out s4 => suff

(x+1)x/2 = 1 + (10+x+1)(10-x)/2 => x^2 + x - 56 = 0 => x = 7

(D) it is 4^17 - 2^28 = 2^34 - 2^28 = 2^28(2^6 - 1) = 2^28 * 7 * 3 * 3 => The greatest prime factor is 7

Total switches = x => Defective switches = (1/5)x => Nondefective swithches = (4/5)x Rejected switches = 4/5(x/5) + 1/20(4x/5) = x/5 => Sold swithches = x - x/5 = 4x/5 Defective sold switches = (1/5)*(x/5) = x/25 => The percent of the switches sold by the factory are defective = (x/25)*100/(4x/5) = 5% Hence, (B) =>

(B) it is PQ = 3 PS = 4 => SQ = sqrt(PQ^2 + PS^2) = 5 PR^2 = 4^2 - RS^2 = 16 - RS^2 PR^2 = 3^2 - RQ^2 = 9 - RQ^2 => 16 - RS^2 = 9 - RQ^2 => 7 = RS^2 - RQ^2 = (RS - RQ)(RS + RQ) = (RS - RQ)*5 => RS - RQ = 7/5 (1) and RS + RQ = 5 (2) (1) & (2) => 2 RS = 32/5 => RS = 16/5 PR^2 = 4^2 - (16/5)^2 = 144/25 => PR = 12/5

(B) it is (1) m^2/n^2 = integer => m and n can be integer or not => insuff (2) m - n = 0 => m = n => m/n = 1 with any value of m and n => suff Hence, (B)

(1) (a - 1)(a + 2) = 70 => a^2 + a - 72 = 0 => a = 8 => suff (2) 2 = 0.25a => a = 8 => suff Hence, (D)

(9,900*1,2) + (13,000*1,1) = 26,180 Hence, (B)

Where is the table? :D

3x/y = prime (*) and y # 3 If: x = a x b (a, b are prime factors of x, b # 3) y = 3 x a (3, a are prime factors of y) => 3x/y = 3*a*b/3*a = b = prime There are many cases for x and y (x = y; x#y) => => (I), (III), (I & III) must not be true and (II) also must not be true Hence, (A)

Many values of (x,y) can satisfy the equation, Apple. It does not mean that the equation has "none" value.

Clearly (D) Naturally occurring chemicals cannot be newly patented once their structures have been published. Before a naturally occurring chemical compound can be used as a drug, however, it must be put through the same rigorous testing program as any synthetic compound, culminating in a published report detailing the chemical’s structure and observed effects.

it = ability to impose a significant fare increase without deterring many price-sensitive passengers

The answer can not be (A), it should be (E)