caldorf

I did not do much specific verbal preparation. I only did official guide sentance correction. I also took every paper test available from mba.com to work on my pacing, which was my biggest problem in my early studying for verbal. See my original post on how I used the paper exams to study. However, I am an avid reader of The Economist and New Scientist, which I read from cover to cover every week. I am also an avid reader of business books. Some of my recent favorites are "the innovator's dillema," "Mastering the dynamics of innovation," Freakonomics, the tipping point, and a number of others. That is in addition to loads of other reading and writing that I do for my job. If you have lot's of time (i.e., a year +) to study, then I would recommend adding both these magazines to your daily/weekly reading regimen. And read some business or science related books.IMO, there is no good alternative to reading often for studying RC and CR. SC is a little different.

I did not retake the GMATPrep tests. I got started on a second try of test 2, and I felt I saw too many questions from the OG, or the previous PowerPrep/GMATPrep tests. Some questions were new, but I did not feel a 700+ plus would prove much, so I stopped. A friend of mine who just got into #1 B-school, and got a 730 on the GMAT, told me I should take the princenton review CATs as a final true test of my abilities. I have to agree, the princeton score came out very close to my real scores. Though not identical to the real exam, it's hardly a big stretch from the PR CATs. My first PR CAT I, with no recognized questions, I got a 44 on the verbal, and I got 44 on verbal on the real gmat. That's close enough for me. I think people put a little too much weight on the GMATPrep versus PR or Kaplan. You have to take the GMATPrep at least once before the real thing, but I would just not place so much emphasis on taking one at the beginning, and the second GMATPrep at the very end, as I think many people have done. Though a good strategy, I wouldn't stress if you've already taken all the official GMAT CATs.

Let me start off by saying that I am happy with my score. It was in the range that I thought I would get; somewhere between 700 and 790 (I know, it's a fairly broad range). This is the first time I have taken the real exam, too. I didn't feel like there were any particularly difficult question on the quant, and was unsure if this meant that I made some stupid mistakes. So when you are taking the exam, don't worry if you don't see crazy difficult questions (a la this site). Also, I was pretty much nervous and stressed throughout the whole thing, which, thankfully, did not cause me to do poorly. Maybe if I was super calm I could have done better??? Who am I kidding, I don't know how much better I could have done even if I was as a calm as could be. GMATPrep 1: 600 (only got through 25 of the quant, and 33 of the verbal) GMATPrep 2: 660 (did not finish either section this time either) Kaplan Diagnostic: 690 Kaplan test 1: 650 (q51, v36) after reading everyone else's Kaplan experience, I felt pretty confident with this score. PR free online test: (q41, v44) took sections separately, so I don't know what the total would have been. Probably around a 700??? PR test 1: 780 (q51, v47) lot's of repeats from free online test PR test 2: 710 (q47, q41), I took this when I was very sick, and hopped up on sudafed and mucinex. This score made me feel confident that if I wasn't high on cold medicine I could probably do a little better In addition to taking loads of practice test, I think my secret sauce was, in fact, the official GMAT paper tests. Though the math and verbal sections are not terribly hard versus the real GMAT, if you time yourself they are challenging. I picked a unique strategy early on in my recent test prep. I was going to figure out how to get a high score without timing myself, and work on my timing when I started getting the scores I wanted. The first paper GMAT I took I got a 640 or so. This was untimed, and demoralizing. After a couple weeks of studying the official guide (10th edition), I took another untimed GMAT paper test, and got a 750. I proceeded to get a 750 on the next three exams I took. My last untimed paper gmat test I got a 780. I then started timing the exams and realized that my pacing was going to kill me on test day. I drilled on only the quant portion of the remaining tests, until I was finishing each quant section within the time limit. I realized that I was not missing more questions, and the additional time from previous test was spent checking and rechecking answers. After I axed the endless answer checking my timing came right into line. I did the same for the verbal sections. On my only properly timed paper gmat test I got a 740. hmmmm... seemed awfully familiar on test day. I feel like the quant and verbal section drilling on the paper tests got me over the 650-700 hump. I recommend everyone download ALL the paper practice tests and do the same thing. This is what got my score above 700. In addition, I found some interesting test prep resources at 4gmat.com, and downloaded all the different $6.99 quant packages, including the 95 question probabilty and permutation test. I don't know if this helped or not after all the other preparation, but I liked the material. It made me feel confident that I could handle anything the test threw at me. Hope this helps all you test takers out there. I have been snooping around this site for a while, and I find the questions a little harder on this site than the actual exam. This is a good thing. The responses from people helped me understand alternative solutions to problems. Using this site really helped round out my test preparation... and it's fun to boot.

Another way to look at this problem: given facts: A) length of street = 3/8 of a kilometer B) Trees consume 1 meter of space C) space between trees 16 meters We know that: C) Number of trees*1 meter + number of gaps*16 meters D) number of gaps = number of trees - 1 see proof of D at bottom We derive: 1. We must convert A) to meters (3/8)*1000 => 3000/8 = 375 meters 2. Number of trees*1 + number of gaps*16 Lets assume X is number of trees. => X-1 number gaps Substitute derived information into equation C => X*1 + (X-1)16 =>X+16X + 16 => 17X =>17X =>X =>X The question asks what is the MAX number of trees on both sides => 23 number of trees * 2 (for both sides of street) = 46 Proof: Consider base case of 1 tree. number of gaps = 1 - 1-> true Assume for N number of trees, number of gaps = N - 1 Consider adding N+1th tree: -> there must be a new gap between the Nth tree and the Nth + 1th tree -> there were N-1 gaps before we added the N+1th tree -> with the additional gap we now have N gaps -> N = (N+1) -1 -> QED

I get 5c4*10c1/15c5 too. Here is the way I thought of it: Probability that 4 are colored and 1 is not colored = number of combinations of five articles where 4 are colored and 1 is not colored chosen from 15 total articles/ total number of combinations 5 arcticles chosen from 15 number of combination of five articles where 4 are colored and 1 is not colored = [A] number of ways to choose 1 of 10 non colored * number of ways to choose 4 from 5 colored [A] * = 1c10 * 5c4 total number of ways to choose 5 articles from 15. [C] = 5c15 [A] = 1c10 = 10 = 5c4 = 5 [C] = 5c15 = 3*7*13*11 = 3003 ans = ([A] * )/[C] =>10*5/3003 =>50/3003 The question must either be copied incorrectly, or the answer key is wrong. Made a mistake. Should have put [C] = 15c5, not [C] = 5c15

The way I thought of it was: We are given facts: A) 10% of total drivers are speeders who got tickets B) 20% of speeder did not receive tickets We derive: 20% of speeders did not get tickets => 80% of speeders got tickets Assume 100 total speeders 80% of 100 total speeders = 80 speeders received tickets Factor that back into A): 10% of [total drivers] = 80 => [total drivers] = 80/.1 =>[total drivers] = 800 percent of drivers that exceeded speed limit = [total speeders]/ [total drivers] => total speeders we assumed to be 100 => total drivers we calculated to be 800 => % of drivers that exceeded speed limit = 100/800 => % of drivers that exceeded speed limit = 1/8 or 12.5% => ans B

You have the problem set up correctly, except you have your equations set equal to 1/x instead of 1. the correct formula is: (1/(3 1/2))x + (1/(4 2/3))x = 1 => (1/(7/2))x + (1/(14/3))x = 1 => (2/7)x + (3/14)x = 1 => (4/14)x + (3/14)x = 1 => (7/14)x = 1 => (1/2)x = 1 =>x = 2

The range of a set of data is the difference between the highest and lowest values in the set. Highest value = 7 Lowest value = 1 range = difference = 7-1 = 6

The range of a set of data is the difference between the highest and lowest values in the set, i.e., highest value - lowest value Highest value:7 Lowest value:1 range = 7 - 1 = 6

solution: probability 2 socks selected are of same color = p(2black) + p(2white) + p(2red) + p(2blue) p(2black) = probability that a black sock is selected first * probability that second sock selected is black =>p(2black) = 20/50 * 19/49 p(2white) = probability that a white sock is selected first * probability that second sock selected is white =>p(2white) = 20/50 * 19/49 p(2red) = probability that a red sock is selected first * probability that second sock selected is red =>p(2red) = 6/50 * 5/49 p(2blue) = probability that a blue sock is selected first * probability that second sock selected is blue =>p(2blue) 4/50 * 3/49 =>total probability = p(2black) + p(2white) + p(2red) + p(2blue) =>total probabilty = (380 +380 +30 + 12) /50*49 = 401/1225

Another way to look at this is a little backwards. The way I solved it, for better or worse, was: 4x + x = Y. =>5x=y =>avg = 5x/6 =>x must have a prime factorization that includes at least a 2 and a 3 => only 48 has a prime factorization that includes a 3 (2*2*2*2*3) =>(b) is the answer

if a != b and (-a,b) and (-b, a) are in the same quadrant, then a and b must have the same sign (i.e. both +, or both -) 1) xy > 0 -> means x an y have the same sign, and both !=0 2) ax >0 -> means that a and x have the same sign so if a and b have the same sign, and a and x have the same sign, then x,y,a, and b have the same sign, which means (-a,b),(-b,a) and (-x,y) lie in the same quadrant. answer is c