I would say D.
Pts to be distributed would be (for 9 places):
5, 4, 3, 2, 1, 0, 0, 0, 0
Maximize one team with 5 & 1 and the other with 4 &2...left with 3.
There may be a hole in that logic, but that's what I came up with in 30 sec!
logic makes sense...but, what's wrong with this formula (it's giving me the incorrect answer):
Time for all 3 to complete one house:
(1/Time) = (1/6) + (1/8) + (1/12)
(1/Time) = 9/24
Time = 24/9 = 8/3 days to complete 1 house if all 3 work together
For 3 houses then, wouldn't it be (8/3) days * 3 Houses = 8 days total (meaning they would finish it together in 8 days)??
What am I doing wrong there?
Makumajon - the logic is correct according to OA reasoning, but your answer is wrong.
x/y R 6...so y>6
a/b R 9...so b>9
means y+b = 6+9 = 15
so y+b > 15...answer E
I actually got 62.8% (none of the above!). I just started with a hypothetical 100 total voters:
- Total 70 for Sobel
- Total 30 for Lange
- 60 males total
- 40 females total
35% of 40 = 14 female voters for Lange which means 26 females for Sobel. If 26 females voted for Sobel, then 44 males voted for Sobel. 44/70 = 22/35 = 62.8%. Don't know if there's a flaw in my logic there...
x, y, a & b are positive integers. When x is divided by y, the remainder is 6. When a is divided by b, the remainder is 9. Which of the following is not a possible value for y+b?
a. 24
b. 21
c. 20
d. 17
e. 15