rajtitan

I'm hearing lot of people saying about 1000 RC.Is there anyone who could help me in getting the link ?

Thanks very much Rakesh. Is there anyone to help me out for 1000 RC please?

I see people recommending usage of 1000RC 1000SC for verbal .Could any one give me the link for that?.I'm searching the net but in vain.

Odd/even cannot be an integer anytime.so IMO A . Odd/odd , Even/odd or Even/even can be an integer

Oh My Bad...I read the 2000$ in the second sentence as 1000$ and hitting the wrong answer which was not in the options..Its just a simple question to put here ....;-(

On a certain day , TIM invested $1000 at 10% annual interest compounded annually, Lana invested $2000 at 5 percent annual interest , compounded annually.The total amount of interest earned by TIM's investment in the first two years was how much greater than the interest earned by Lana's investment in the first two years? I donno the options but the answer is 5$. Can anyone explain?

M = Square root (4) + Cube root (4) + Fourth Root (4) Whats the value of M ? A) Less than 3 B) Greater than 3 C) Greater than 3 and less than 4 D) Equal to 4 E) Greater than 4 Answer is C) Could anyone explain how to solve this ?

Detailed explanation of this problem for those who are beginning P&C First Day Choice: 3C1*3C1*2C1 ( One from three shirts, one from three pants, one from two pair of shoes) Second Day Choice : 2C1 * 2C1* 1C1 ( One from two shirts(one shirt is already selected) , one from two pants(one pant is already selected), one from one pair of shoes (same shoe for the second day) Third Day Choice : 1C1 *1C1*1C1 (one shirt , pant and one pair of shoe(same shoe)) So the combination for three days is (3C1*3C1*2C1) *(2C1 * 2C1* 1C1)* (1C1 *1C1*1C1) -----> 1 Total possible combination for three days without constraint(i.e selecting one on each day) is (3C1*3C1*2C1) *(3C1 * 3C1* 2C1)* (3C1 *3C1*2C1) ------> 2 Probability = favorable Events / Total Events Therefore dividing 1/2 we get (1/3)^4 , Answer C

You did great even in the tough circumstances..best of luck in your applications

Bearkill, Your post is much encouraging ..thanks..

80% atleast more than 25 so 20% less than 25 .Let x be the total package then 20% of x = 48 ==> x = 240 60% weigh less than 75 which is equal to .6 * 240 = 144 therefore the answer is 144 -48 = 96 IMO C

f(K) =k^5/16 makes sense as f(2k)= (2k)^5/16 ==> (2^5)(k^5)/16 ==> (32)((k^5)/16 ==> 2(K^5) Hence f(2k) /f(k) = (2(K^5)) /(k^5/16) = 32

Great !!!..You might be with the creamy few group

take r = .9 and S = 1.9 1) .9/1.9 should be less than 1 2) r.s = .9 * 1.9 > 1 3) 1.9 - .9 = 1 = 1 so 1) only is the answer option A

Thanks Vgp

I get the boundary 6 and 24 but how its exclusive..thats the part I'm not getting..Please some one help on this..

If |x| So I holds true II Always cannot be true , x can be negative too X So A) is the answer

D it is

Please let me know that my approach is correct on solving the equation we get x as 0, 5 and -2 The two equations in 1) and 2) is true for all the values of x (0,5 and -2) So its E

Great explanation ..ann

I got 3.1 .I go with D.It got to deal with the reading of the question

The possible places for 2 ‘R’s in this case is 1 &5 , 1&4 , 2 & 5 # of ways in which ‘ R’ are in 1&5 is 3! ( 1& 5 will not change 3 places are there and can be filled in 3 factorial ways ) Similarly # of ways in which ‘ R’ are in 1&4 is 3! Similarly # of ways in which ‘ R’ are in 2&5 is 3! Total probability is 3! + 3! + 3! = 18 Answer is B

IMO B.This type of problems can be solved by taking the unknown value as X and then think of the equation ...

Imo 2

Good Explanation Cesar ..