Megamind

I forgot that they're squares, thanks!

Square root √ always gives a +ve value A) 7 B) √(36+49) = √85 > 9, so B is bigger

D cause you don't know the other probability, so you can't calculate each one separately

intuitively I feel it's C

x+x+2c+x+4c = 27 3x+6c=27 x+2c= 9 x+c+x+3c 2x+4c 2 (x+2c) = 2 * 9 = 18

A) 7w-4 B) 2w+5 A) 5w - 9 B) 0 A) 5w B) 9 if w = 2, A is bigger (=10) if w= 1.5, B is bigger (as A = 7.5), so D

we know Q3 = 35, then how to do this one?

Magoosh is overpriced ($199), archaic-designed, and lacks social features. Compared to Grockit, I play 10-20 questions per session on magoosh, compared to 70-100+ on Grockit. Perhaps adding similar features will attract more students? Till then, I think you should lower your price or give me more reasons not to give the $199 to Kaplan.

stick with major test-prep companies (Manhattan, PR, Kaplan (although their CD is crap), McGraw Hill..etc) and skip crappy websites like grockit, majortests, magoosh, greguide...etc

"The sum of the ages of mother and daughter is 50 years. Also 5 years ago, the mother age was 7 times the age of the daughter. Find the sum of the ages of mother and daughter after 5 years?" let m = mother, d = daughter m + d = 50, or m = 50 - d 5 years ago: m - 5 = 7 (d-5) m - 5 = 7d - 35 50-d-5 = 7d-35 8d = 80 d = 10 m = 50 - 10 = 40 sum of both 5 years ahead i.e (m+5) + (d+5) (40+5) + (10+5) = 60

so as not to confuse yourself, area of equilateral tri = (S^2 √3)/4

10, as 1/1024 will be

Q.1. Ten different letters of an alphabet are given. 2 of these letters followed by 2 digits are used to number the products of a company. In how many ways can the products be numbered? 10*9*10*9 = 8100 Q.2. How many five digit numbers can be formed using 0, 2, 3, 4 and 5 when repetition is allowed, such that the number formed is divisible by 2 or 5 or both? 4*5^3* 5 - 4*5^3 * 1 = 2500 - 500 = 2000 Q.3. There are 12 children in a party. In how many ways can different pairs be made? 12C2 = 12*11/2 = 66 Q.4. How many different differences can be obtained by taking only two numbers at a time from 3, 5, 2, 10 and 15? IMO 18, there're 20 differences you can get, for different remove (5-10 same as 10-15, and 10-5 same as 15-10)

"The function of f is defined for all numbers x by f(x)=x^2+x. If t is a number such that f(2t)=30, which two of the following could be the number t?" Indicate two such numbers. -5, 3-, -1/2, 2, 5/2 f(2t) = 4t^2 + 2t = 30 4t^2 + 2t - 30 = 0 (divide by 2) 2t^2 + t - 15 = 0 (2x-5) (x+3) = 0 x = 5/2, x= -3

Plugin numbers A) a^-10 = 1/(a^10) B) 1/(b^5) if a= -1 and b = 1 A) 1/(-1^10) = 1 B) 1/1^5 = 1, so C if a = -2, and b = 1 A) 1/(-2)^10 = 1/2^10 B) 1/1^5 = 1, so B is bigger so it can't be determined, D