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Compilation of some tough problems


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Thanks guys! I take GMAT on saturday. I think I should be okay if I get 600ish to get into the program I am looking at. If I get the score I want in my first attempt and get into this program I am looking at (I will know in 2-3 weeks after my exam), I have promised myself that I will donate all my GMAT prep material to all you fellow testmagicians. Please keep your fingers crossed for me.

 

 

Thank you!:luck2:

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  • 2 weeks later...

Security Geek,

This is a great compilation.

 

An alternative way 2 solve this problem.

 

31. If Bob and Jen are two of 5 participants in a race, how many different ways can the race finish where Jen always finishes in front of Bob?

 

 

Ans : Total number of ways of arranging 5 participants = 5! = 120.

In, half of these arrangements Jen will finish ahead od Bob .

So, no of arrangements = 120/2 = 60

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54. Two people walked the same distance, one person's speed is between 25 and 45,and if he used 4 hours, the speed of another people is between 45 and 60,and if he used 2 hours, how long is the distance?

A.116 B.118 C.124 D.136 E.140

Soln : A

Let A be the person walking with speed between 25 and 45. 25

Let B be the person walking with speed between 45 and 60. 45

TimeA = time taken by A to cover the required distance d = 2 hrs.

TimeB = time taken by B to cover the same distance d = 4hrs.

As the distance is same.

(TimeA/TimeB)=(SpB/SpA)=4/2=2/1.

There fore the possible combinnations for SpA,SpB based on the constraints =

(25,50)

(26,52)

(27,54)

(28,56)

(29,58)

(30,60)

As , we know time taken by A = 4hrs, the only answer that matches the option is 29*4=116. Hence , A.

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I am getting a different answer to question#1.

 

Sum of even numbers between 1 and n = 2 + 4 + ...+ (n-1)

= 2(1 + 2 + ..(n-1)/2) = (n-1)(n+1)/4

So we get the equation: (n-1)(n+1)/4 = 79*80

which reduces to (n-1)(n+1) = 158*160

from which we get n = 159.

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I am getting a different answer to question#1.

 

Sum of even numbers between 1 and n = 2 + 4 + ...+ (n-1)

= 2(1 + 2 + ..(n-1)/2) = (n-1)(n+1)/4

So we get the equation: (n-1)(n+1)/4 = 79*80

which reduces to (n-1)(n+1) = 158*160

from which we get n = 159.

 

 

  • The sum of the even numbers between 1 and n is 79*80, where n is an odd number, then n=?

n*(n+1) = 79 * 80 ==> n =79:D

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  • 1 year later...

guys have my GMAT on the 10th of jan...finding some of these problems real tough to do...am consistantly scoring 48 in my GMAtprep tests and am able to do the GMAT sets under timed conditions getting only 5 wrong or so,

 

are these real GMAT questions and are we likly to see questions of this level in the exam,kinda nervous after looking at these questions.

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