rits700

one more GMAT trap.....:hmm:

Q1) imo A each shirt costs $15 each sweater costs $25 avg given as $21 => 15x + 25y = 21(x+y) => 3x=2y clearly the number of sweaters sold(y) is greater than the number of shirts sold(x). SUFFICIENT stmt2: the total price for shirts and sweaters = $420 => 15x + 25y = 420 => x & y can be (23, 3) OR (8, 12) so number of sweaters sold can be greater OR less than the number of shirts sold. INSUFFICIENT. Q2). refer this Q4) imo D x & y are +ve integers, is xy even? stmt1: 5x-4y even since 4y is even for any integer value of y, 5x has to be even, since given that 5x-4y even. => 5x is even => x even => xy is even. SUFFICIENT stmt2: 6x+7y is even since 6x is even for any integer value of x, 7y has to be even, since given that 5x-4y even. => 7y is even => y is even => xy is even. SUFFICIENT

imo A. statement-I alone is sufficient to reach to the answer. mean of 10 one digit numbers is 8.8 => sum total is 88. in order the sum total of 10 one digit numbers to 88, there has to be at the least eight 9s and others 2 can be 8s e.g., the series can be 8,8,9,9,9,9,9,9,9 OR 7,9,9,9,9,9,9,9,9 can u think of any other set of numbers - I think NO. so in any case the median will be 9. and this is what the Q is asking. SUFFICIENT.

T-REX, Gaurav, How do you justify the usage of past perfect tense in chocie B?? In 1981 children in the United States spent an average of slightly less than two and a half hours a week doing household chores; by 1997 that figure had grown to nearly six hours a week. it doesn't seem to be a GMAT type Q, but given the choices, D is the lesser evil as most of us agreed....

if u square both sides, everything gets cancelled out. so it gives nothing. so A is INSUFFICIENT Hence as explained by arjmen, ans shd be E

M+W=1400 (equation-I) 42% of 1400 = 36% of M + 50% of W. (equation-II)

I think the prediction happened much before the economy growth. so past perfect is natural choice.

one more vote for B

B makes sense.

how it results in different values as sum?

imo E. both the choices essentially gives the same info in a different way and it is not SUFFICIENT

we are comparing "mathematics" with "a creative activity". It certainly is not a NOUN comparison. when we compare "mathematics" with "activity" - it is NOUN comparison geekybiz1, you could be right. I think the second reason sounds great. I buy that.

A it is. discussed many times in the past. 3y^2+7y=x =>y(3y+7)=x since given that x & y are integers, hence x is multiple of y. SUFFICIENT

thnx. OA is A. it's a kinda tricky Q. tempting to go for C.

thnx GMAT-HELP for the explanation. The answer indeed is E.

What is the standard deviation of Q, a set of consecutive integers? (1) Q has 21 members. (2) The median value of set Q is 20.

10^25 – 560 is divisible by all of the following EXCEPT: a. 11 b. 8 c. 5 d. 4 e. 3

E is not the answer. The words "causing" and "starting" illogically refer back to the economic recession. In fact, the falling employment rates, not the economic recession, cause the cutbacks in consumer spending and start the cycle of layoffs. in C if which modifies "investment" then shouldn't the sentence read "which causes" but the choice C has "which cause" then clearly, "which" is not modifying "investment" as it appears.

stmt1 is valid for z=1 and n any non-zero integer value stmt1 is also valid for z=-1 and n=2 so from stmt1: z can be +1 OR -1. INSUFFICIENT from stmt2: z>0 => z can take any value greater than 0. INSUFFICIENT from stmt1 & stmt2, clearly z=+1. SUFFICIENT

i had come across this Q in manhattan and answered it wrong. the correct answer and the explanation given by manhattan is not convincing enough. needs little debate..... let the show go on....

C is better. we are certainly not comparing two nouns here. we are comparing "mathematics" and "a creative activity", so "AS" is more appropriate here. if it was between "mathematics" and "physics" then "LIKE" would have been good. Teachers in this country have generally been trained either to approach mathematics AS a creative activity or to force students to memorize rules andwithout truly understanding how to apply them.

imagine the 2 numbers n & t as 10 & 35. it satisfies statement-I that the greatest common factor of n & t is 5. However greatest prime factor of the product(10*35=2*5*5*7) will be 7. so statement-I alone is NOT SUFFICIENT.

we can derive the value with only A. since the ratio of speeds 3:2 and the total distance in-between them is 200. for any value of speeds that satisfy the ratio 3:2, when they meet each other the sparrow might have travelled a distance of 120 feet. so A is SUFFICIENT. a tricky question...

discussed many times in the past. 4^17 - 2^28 = 2^34 - 2^28 = 2^28(2^6-1) = 2^28*63 = 2^28*7*3^2 so prime factors are 2, 3 and 7. => greatest prime factor is 7

thnx kum_012 for pointing out the mistake. I have edited my earlier post. I hope I don't this kinda silly mistakes on DDay.