amithravindra

IMO since C and E is irrelevant.D would strenghten the argument. IMO A

Imo C

it definetly cant be 91 45 45 as the two sides are not equal.only in isosceles triangle this will happen.

W=(10!*11*12)-(10!-11)-10! TAKING 10! COMMON W=10!(11*12-11-1) W=10!(132-12) w=10!(120) WE KNOW THAT ODD*ODD=ODD EVEN*EVEN=EVEN ODD*EVEN= EVEN SO TO FIND IS Z(Y+1)IS ODD WE NEE TO KNOW IF ONE OF THE ie IF Z IAS ODD OR EVEN OR if y is even then y+1 is odd and if Y is odd then Y+1 is even Statement 1: 10^ (any number) is always odd as it end with a zero and if we add 2 to it it will always be an even number.so wiyh statment 1 we can tell that Z(Y+1) is always even statement 2: 2^X is the highest factor of W so we need to find the highest power of 2 in 10!(120) tHE HIGHEST POWER OF 2 IN 10! IS 2^8 AND THE HIGEST POWER OF 2 IN 120 IS 2^3.TOGETHER IT ADDS UP TO 2^11 SO y IS 11 THEN y+1 IS ALWAYS EVEN SO Z(Y+1) IS ALWAYS EVEN THEREFORE THE ANS IS D imo

This is clearly a cause and effect.When two events occur simultaneously.THe reasoning is drawn in a wrong way by assuming that one evnt actually caused the other.It could be that both the evnts might have been caused by an independent evnt or it might be that what is assumed as the cause is the effect and vice versa.Option C it is for me.OA please

here use the concept of manhours man hours=number of men involved *number of hours each man works so the manhours for the job=6*10=60 manhours from 12:00 pm to 6:00 pm 6men work for 6 hours so manhours spent is 6*6=36 the defeciet is 60-36=24 from 6:00 to 7:00 7 men work for 1 hour =7*1=7 manhours from 7:00 to 8:00 8 men work for 1 hour =8*1=8 manhours from 8:00 to 9:00 9 men work for 1 hour =9*1=9 manhours total=24 manhours the work is done by 9:00pm oops thats should have been beaverhours i guess

the set {1,2,3,4,5,6} has 6 numbers so the event has 6P2 combinations which is 30 events the favourable events (1,3)(3,1)(5,4)(4,5)(6,3)(3,9) which is a total of 6 events probability 6/30=1/5 IMO 1/5

1/2*10^35(here 10^35=(2*5)^35) therefore 1/2^1*10^35 =1/(2^1*2^35)*5^35 =1/(2^36)*(5^35) =1/(4^18)*(5^35) (1/4)^18* (1/5)^m =(1/4)^18*(1/5)^35 IMO ans 35

1/(2^10) + 1/(2^11) + 1/(2^12) + 1/(2^12) here the last 2 terms reduces to (1/2^12) + (1/2^12) = 2/(2^12 )= 1(2^11) 1/(2^10) + 1/(2^11) +1/(2^11) here the last 2 terms reduces to(1/2^11) + (1/2^11) = 2/(2^11) = 1/(2^10) 1/(2^10)+1/(2^10) = 2/(2^10) = 1/(2^9) ans is 1/2^9

i agree with rdabas the no of cans is 5*4=20 only

shingivyas 5" is not possible as the face ur placing the cylinder has length as 10" but breadth as 8" so a cylinder which has diameter as 10" will sit along the length but not the breadth as it is only 8".try drawing the figure it will be much clear

Volume of cylinder Pi * (d^2/4) * h the cylinder can be placed on three faces of the box the details are as follows The diameter of the cylinder that can be placed in the box on the 6" x 8" face is 6" and ht is 10" - Volume is 90Pi (always take the lowest of the 2 dimensions) The diameter of the cylinder that can be placed in the box on the 6" x 10" face is 6" and ht is 8" - Volume is 72Pi The diameter of the cylinder that can be placed in the box on the 8" x 10" face is 8" and ht is 6" - Volume is 96Pi so IMO the ans is B

what if the number itself is a prime number

Imo E

i agree with robbiecool the avg has to be taken after the year 1946 so this year doesnt count in the avg

agree with KBTA it is a gp with r=2

i am not sure DIGVIJ for example 12 has factors 1,2,3,4,6,12 but 12+1 changes the whole situation as 13 has only 1 as factor the problem as pawan said reduces to {(2^50)*50!}+1 trying hard to go ahead but still stuck here

i am very sory for the wrong post was in a hurry at the office plzzz excuse me ,will get back with the ans soon i promise

sorry wrong method

numerator (1+1/3)(1+1/4)(1+1/5)(1+1/6)(1+1/7) can be written as =(3/3+1/3)(4/4+1/4)(5/5+1/5)(6/6+1/6)(7/7+1/7)(plzz note every place 1 is written as the 3/3,4/4,5/5,6/6 and 7/7 for convenience sake to solve easily) =(4/3)*(5/4)*(6/5)*(7/6)*(8/7) =8/3 denominator (1/3)+(1/4)+(1/5)+(1/6)+(1/7) =(420+315+252+210+180)/1260 =1377/1260 therefore =numerator/denominator =(8/3)*(1260/1377) =1120/459

54root(3) - 27Pi. is the ans circumscribe the hexagon and and draw radius to the circumcircle find the interior angle of the hexagon u'll find the individual angle of the triangle formed by the radius of the circle and the side of the hexagon will have each angle equal to 60 degree(use the threom angle oposite to equal sides are equal)

man hours = number of men involved *number of hours each man works so the manhours required for the job=6*10=60 manhours from 11:00 am to 5:00pm 6 men work for 6 hours so manhours spent is = 6*6=36 the defeciet is 60-36=24 from 5:00 to 6:00 7 men work for 1 hour =7*1=7 manhours from 6:00 to 7:00 8 men work for 1 hour =8*1=8 manhours from 7:00 to 8:00 9 men work for 1 hour =9*1=9 manhours total=24 manhours the work is done by 8:00pm

12*10*8*5*2 = 9600.u Have Forgotten The Cream

C+8X=257---eq1 C+8Y=185---eq2 eq1-eq2 8X-8Y=72 8(X-Y)=72 X-Y=72/8=9 X-Y=9 WE KNOW THAT X=1.8Y THEREFORE 1.8Y-Y=9 Y=9/0.8 THEN 8Y=8*(9/0.8)=90