vvv134

Just keep practicing, youll be able to see the connections better.

taking the gre is like playing a game. All you have to do is to understand the rules and practice as much as you can. Many experts agree that the gre may not be the best way to gauge your analytical or quantitative skills nor is it representative of how you will perform in graduate school. Ive seen many of my friends who are awesome in math get pretty low quants scores.This is because Your performance is dependent on more than just your thinking ability . These scores have very little to do with how intelligent you are or how you will turn up in life

didnt understand what you did.Is marked price same as s.p?

you are right.there are no restrictions on values of m and n.hence,for any value of m,there can be a value of n such that the equation is met.so D

std deviation is a representation of how far a set of values are dispersed around the mean.A high std deviation would mean an overall high deviation from mean and vice versa.in the gre,you would never be asked to calculate std deviation,so dont worry about the formula.they would most likely ask you to compare std dev of 2 sets of observations.

it cant be A.to deceive ,the reasonig has to be seemingly true but actually false.in other words,it has to be cogent or convincing.But it doesnt deceive anyone because its specious.

no it doesnt.one angle is 90 deg.the other two angles can be anything that adds up to 90 degrees.

for the 9th one,i think y would be a higher degree of x.so answer should be c.

p(a not hitting target)=3/4 p(b not hitting)=3/5 prob that target is hit = 1-(p(a)*p(b))=11/20.

your approach is correct.since the answer choices state conditions,you can plug in values to see if that condition is always met.for example,you know every prime number is an integer,so a must be a multiple of 7. now plug in a=42*7,b=6 then a/7*b =7 which is a prime number.but b is even and a is even and b is not a prime number.so answer must be 1 only.

ya,plugging values is good for these kind of problems.

if you take 0 as one of the integers a,b,c,then result would be an integer 0.and if you take any other possible values of a,b,c without 0,then you would have 1 multiple of 3.

easiest way to do this problem would be to consider each team.If you take a team out of 8,then that that team plays against the remaining 7 teams.then remove this team.a remaining team would need to play against 6 teams and so on.so 7+6+5+...+1=28.

i think the range is 0

if you keep adding 3 to -8,then you would need to add 64 times to get 184.hence,no of terms is 64+1=65.(since you need to include the first term -8).

just analyze both cols first.col a would be (20-21)/(4-5) not inclusive of extreme values. col b would be (5-6). since col A can have values both greater than 5 (20.9/4.1) or lesser than 5(20.1/4.1),the answer would be D.

yes,it is very important in the gre to consider all possibilities,not only integers,if not specified.

for an integer that is.

yes any number is a multiple of itself.

given n is a multiple of d.so no of pos multiples of d less than n should be n/d.example 4,2.both 4,2 are

inflate:burst should be pull:tear

youre right.trouble is a state of mental agitation.so distraught can be an extreme form.but all answer choices seem to be adj:adj.if the question was troubled:distraught,then i can agree with the choice C.

the high frequency words do repeat often in the gre.But its a risk studying only these words.its better if you study these words first thoroughly and then do as many words from barrons list as you can.

i concur.choice b must be the answer.answer E goes agains what the author states in the last para.

D worked for 4 days,m for 1 day and both 10 days.let D alone take x days and M alone y days. then 4(1/x) + 1(1/y) + 10x+10y/xy will be the total rate. = (11x + 14y)/xy. =11(1/y) + 14(1/x). thus,if D alone works for 14 days and M alone for 11 days they can finish the work. since they get paid same amt/day,Ds pay is 14/(14+11)*3000.