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a4nsd

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Everything posted by a4nsd

  1. we can eliminate A,C,E because of not using parallelism : either using... or + using... There are only B, D left.Let look at the verb exhibit. the subject here is the"animals" plural. therefore D is the final answer.
  2. I found the answer from another web site
  3. No way. You divide both sides by Y but you forget the condition that Y>0. If Y to For example if x = 2, y = -3 then 7x-2y = 16 + 6 > 0. INSUFF 2. Is also insuff ; for example y = -3; x = 5 we also have -(-3) Both combine are also insuff. therefore E is my answer
  4. Yeah. I think C. $=4 is insuff because @ and # can be (3,1) if @>1, @ can be 2 or 3; if @ = 2 then # must be 2. this can not happen 'cause @,#,$ are different. therefore @ can only be 3 and # = 1 SUFF
  5. A is the correct answer because. x^2 >9 means x>3 or x
  6. Here is the definition based on GMAT Review "The number -2,-1,0,1,2,3,4,5....are consecutive integers. Consecutive integers can be represented by n, n + 1, n+2, n+3... where n is an integer. The numbers 0,2,4,6,8,...are consecutive even integers, and 1,3,5,7,9...are consecutive odd integers. Consecutive even integers can be represented by 2n,2n+2, 2n+4...., and consecutive odd integers can be represent 2n+1, 2n+3, 2n+5.... where n is an integer."" Hope this help
  7. Another solution We must compare 3^5 and 5^3. Divide both side by 3^3 thus we compare 3^2 with (5/3)^3. 9 ? (5/3)^3. Notice that 5/3 In conclusion 3^5 > 5^3
  8. Clearly x = 19. To find y, assume that the Math and English students overlap as little as possible. Since there are 5 students who are not taking Math, the smallest overlap is 22- 5 = 17. Then if the History students overlap the 8 math students not taking English and the 5 English students not taking math, there must be 19 - 5 - 8 = 6 history students also taking both Math and English. Thus y = 6 and x + y = 25 hence the final answer choice is E
  9. For #1. I got the answer from another website. Hope this help
  10. For # 2. IMO the answer is e: 27 because We have 2 selections that offer the same kind of cheese and fruit. 1. Each platter contains 1 cheese and 1 fruit ;therefore we have 6x2 = 12 options 2. Each platter contains 2 fruits and 2 cheese -> we have 6!/2!(6-2)! = 15 options Total 1 + 2 = 12 + 15 = 27 Is there another idea?
  11. Yes, I have the same solution. You know most of the math in GMAT do not require us to compute so much. there is always a "shortcut" way to solve them
  12. You can try Visual Thesaurus dictionary. It is very helpful to learn new words
  13. I think A is more convincible ...
  14. I especially want to say thank to score. He is very enthusiastic to answer the questions. I'm new here and i'm preparing to take the TOEFL and GMAT next month. Hope that I can pass . Amen
  15. Thanks very much. That is what I've learned from my teacher
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